I have written a code that generates 20 strings (the number actually varies depending on the input), all of which have the names "s_idx_?" where ? is a number from 1 to 20. Is there a command that allows me to concatenate all these strings without having to type out all the names? Thanks.

5 Comments

First: it is generally nicer to create one data structure to contain all of these strings rather than creating a variable per string. Look up cell arrays, they are your friend. Rather than calling your strings s_idx_?, you could just call them s{?} where ? is your old number.
E. Elgar
E. Elgar on 19 Jul 2011
Actually I'm oversimplifying the problem a bit. This is the code I have:
for e = 1:length(c)
f = eval(c{e}); % for each c, f gives the list of cues under the condition
for g = 1:length(f) % runs through the whole string of cues (f)
i = f{g};
h = genvarname('s_idx_',who);
eval([h '= find(strcmp(''' i ''',theData.study.cue))']); % matches each i with a number from some list I have
end
end
The output is a bunch of variables called "s_idx_?". The number of variables will change if I change the input. I've tried creating cell arrays as Nathan suggested, but it doesn't seem to work.
POISON!! EVAL!! Don't do it!!
E. Elgar
E. Elgar on 20 Jul 2011
!! Other solutions then?

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 Accepted Answer

Don't do it!
but if you have to:
sprintf('s_idx_%i\n',1:20)

1 Comment

Jan
Jan on 20 Jul 2011
I agree with "Don't do it". The SPRINTF command concatenates the _names_ of the variables?! The OP wants to cat the string values.

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More Answers (1)

Jan
Jan on 20 Jul 2011
Follow Sean's link to the FAQ. There you find the suggestion to use a cell like "s_idx{i}" instead of including the index in the name of the variables. Thjen the concatenation is easy:
s = cat(2, s_idx{:});

1 Comment

E. Elgar
E. Elgar on 20 Jul 2011
Thank you! I think this will work.

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Asked:

on 19 Jul 2011

Edited:

on 12 Sep 2023

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