How to sum specific value in 1:m ?

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Mech
Mech on 10 Jun 2014
Answered: Mech on 11 Jun 2014
  • m=1:2
  • b(m)=sum(sin(1:m)*b)
  • then the result
  • b(1)=sin(b)
  • b(2)=sin(b)+sin(2*b)
  • But I need
  • b(1)=sin(b)
  • b(2)=sin(b)+sin(3*b)
for n
  • b(n)=sin(b)+sin(3*b)+sin(5*b)+sin(7*b)...
  2 Comments
Mech
Mech on 11 Jun 2014
Edited: Mech on 11 Jun 2014
  • thank bro.
  • I have just find solution
for m=1:5
f(m)=2*m-1
b(m)=sum(sin(f)*b)
end

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Accepted Answer

Mech
Mech on 11 Jun 2014
for m=1:n
f(m)=2*m-1
b(m)=sum(sin(f)*b)
end

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