# HOW TO ENCODE AN 8BIT VALUE FROM A MATRIX

2 views (last 30 days)
Abirami on 14 Aug 2014
Edited: Abirami on 15 Aug 2014
HELLO
I have generated a 256x256 matrix with an 8bit binary sequence present in each element. I wish to encode the sequence using the following scheme
A=00
B=01
C=10
D=11
clc
clear all
close all
imshow(a)
disp(a)
for i=1:1:256
for j=1:1:256
b{i,j,1} = dec2bin(a(i,j),8);
end
end
disp(b)
M=randint(256,256,[0,256]);
disp(M)
for k=1:1:256
for l=1:1:256
N{k,l,1} = dec2bin(M(k,l),8);
end
end
disp(N)

Pratik Bajaria on 14 Aug 2014
Hello, Check this. I think it would work for you. It worked for me fine.
for i=1:size(b,1)
for j=1:size(b,2)
dum=0;
for k=1:2:size(b,3)
dum=dum+1;
if (b(i,j,k)*10+b(i,j,k+1))==00
test(i,j,dum)='A';
elseif (b(i,j,k)*10+b(i,j,k+1))==01
test(i,j,dum)='B';
elseif (b(i,j,k)*10+b(i,j,k+1))==10
test(i,j,dum)='C';
else
test(i,j,dum)='D';
end
end
end
end
Please let me know in case of further doubts.
Regards, Pratik
Abirami on 15 Aug 2014
sir, im not able to follow...i tried but im getting the following error
Attempted to access b(1,1,2); index out of bounds because size(b)=[256,2048,1].
Error in ==> prat1 at 20 if (b(k,l,m)* 10+b(k,l,m+1))==00
also im not able to view the result...pls help..thanks in advance

David Sanchez on 14 Aug 2014
M=randint(256,256,[0,256]);
disp(N)
N=zeros(size(M));
for k=1:256
for l=1:256
N(k,l) = str2double(dec2bin(M(k,l),8));
end
end