Integral a function handle of two variables with respect to a variable

f = @(x, y) x+y;
g = @(x) integral(@(y) f(x,y),0,1)
t = (0:0.1:1);
g(t)

It is wrong! How can I get the expected result？

Answer 1

[Walter Roberson]

f = @(x, y) x+y;
g = @(x) integral(@(y) f(x,y), 0, 1, 'arrayvalued', true)

g = function_handle with value:
    @(x)integral(@(y)f(x,y),0,1,'arrayvalued',true)

t = (0:0.1:1);
g(t)

ans = 1×11

0.5000 0.6000 0.7000 0.8000 0.9000 1.0000 1.1000 1.2000 1.3000 1.4000 1.5000

[Jingyu Liu]

Thanks!