Decompressing *.7Z Files with MATLAB
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I have a 7z file. I wish to decompress it using Matlab. How can I do this? The inbuilt matlab functions dont support it.
I have tried,
[status,result] = system(['"C:\Program Files\WinRAR\UnRAR.exe" e ' E:\myFile.7z ' >null']);
however this fails as it gives
result =
UNRAR 5.11 freeware Copyright (c) 1993-2014 Alexander Roshal
E:\myFile.7z is not RAR archive
No files to extract
On closer inspection unrar.exe is not the same as winrar (which can do 7z). Hence i download 7-zip
[status,result] = system(['"C:\Program Files\7-Zip\7z.exe" e ' E:\myFile.7z]);
result =
7-Zip [64] 9.20 Copyright (c) 1999-2010 Igor Pavlov 2010-11-18
Processing archive: E:\myFile.7z
Error: Can not open file as archive
any ideas?
thanks
Accepted Answer
More Answers (1)
Jake August
on 19 Apr 2016
This was very helpful. Someone else looking might find this useful.
% for 7zip 15.14 x64
file7z = 'D:\my.7z';
% rest of code
[dir7z,~,~] = fileparts( file7z );
dir7z = ['"' dir7z '"'];
file7z = ['"' file7z '"'];
[status,cmdout] = system( ['"C:\Program Files\7-Zip\7z.exe" x -o',dir7z,' ',file7z] );
3 Comments
ZHIWEI WANG
on 11 Jun 2021
It works well!
Verena Schwachmeyer
on 13 Jun 2022
Hi Jake August,
thank you. Your solution works for me - but only if I run it once. When this operation is part of an iteration, Matlab freezes during the second loop. Do you have an idea why that is and how to fix it?
-Verena
Walter Roberson
on 13 Jun 2022
Perhaps using .NET Systems.Diagnostic.Process() to start the process instead of system()
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