[y,Fs] = audioread('C:\Users\Casper\Desktop\3.3V.wav');
L=length(y); % series length
;
f = Fs/2*linspace(0,1,L/2+1); % single-sided positive frequency
X = fft(y)/L; % normalized fft
PSD=2*abs(X(1:L/2+1)); % one-sided amplitude spectrum
figure,plot(f,PSD);
grid
xlabel('freq(Hz)')
ylabel('amplitude')

 Accepted Answer

Try this —
idx = (f <= 1500) & (f <= 1800)
[rpm, freq] = findpeaks(PSD(idx), f(idx), 'MinPeakHeight',0.75E-3)
Without the data, I cannot experiment with that, however it should return the peak value as ‘rpm’ and the frequency as ‘freq’. If it does not, experiment with 'MinPeakProminence' instead of 'MinPeakHeight' since it cannot be determined from the plot that there are not more components to the desired peak.
.

2 Comments

Thank you king
As always, my pleasure!
.

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More Answers (1)

Voss
Voss on 28 Dec 2021
You could use Data Cursor to create a datatip, or you could try something like this:
idx = find(f(:) > 1000 & f(:) < 2500 & PSD(:) > 0.00075);

3 Comments

burak Kalayoglu
burak Kalayoglu on 28 Dec 2021
Edited: burak Kalayoglu on 28 Dec 2021
I want to find a value1698 (signed point in graph) but ı cant , ı want to find signed point and after ı can find rpm this signal
What does this do?
f(1698)
PSD(1698)
Because I want to see what corresponds to the same psd value in different signals

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