What is the meaning of this code snippet?

function Average(Obj,signal,AnalysisType,TimePoints,varargin)

if nargin==3

ExtSeg=varargin{1};

else

ExtSeg=0;

end

Answer 1

[Les Beckham]

What that looks like it is trying to do is to check to see if the caller provided an optional argument and setting the variable ExtSeg equal to the value of that optional argument if it is present or to zero if it is not.

However, since the function has four named arguments already, this probably isn't doing what was intended.

If the test was if nargin == 5 instead, then I believe it would work correctly.