How to make a function that outputs true or false (logical) if a number inputted is in a predetermined vector?

% Here is my code:

function [x] = testLucky1
% testLucky(x) - determine whether x is a lucky number
% return true (1) if x is a lucky number
% return false (0) if x is not a lucky number

secretLucky = [19,22,5,9,11,15,21];

x = input('Enter a number: ');

for k = 1:length(secretLucky)
   if secretLucky(k) == x
       true
   else
       false
   end 
end

% The issue I'm having is that when I enter a single number like
% 19/22/5/9/11/15/21, the command window shows a logical statement of 1
% alongside logical statements of 0.

% For example, if I input 19, the first logical statement in the command
% window will be 1, and the remaining 6 logical statements will be 0.

% My question is, how can I make the output in the command window be a
% SINGLE logical statement of 1 if ANY of the numbers in vector secretLucky 
% is entered? And if a number that is not ANY of the numbers in vector
% secretLucky is entered, how can I have a SINGLE logical statement of 0?

% Does my issue stem from the fact the ouput of true/false is based on my
% variable k? If so what should I do to change this?

Answer 1

[Walter Roberson]

found = false;
for k = 1:10
  if x(k) == 7
    found = true;
  end 
end 
found

[Jacob Boulrice]

Hey, thank you for the response.

Any chance you could explain what this means? And where I should add this in my code?

One question I have is why you set k to 1:10?

[Walter Roberson]

The intent is to illustrate initializing a state variable, changing it conditionally, and then examining the state afterwards.

Key point: do not display true when you find a match, set the state variable instead. And do not display the false when a match fails, just go on to the next test. You do not care in this context whether the input did not match 7 out of the 8 possibilities: you only care that it matched one of the possibilities.

Answer 2

[Davide Masiello]

function testLucky
% testLucky - determine whether x is a lucky number
% return true (1) if x is a lucky number
% return false (0) if x is not a lucky number
secretLucky = [19,22,5,9,11,15,21];
x = input('Enter a number: ');

result = false;
for i = 1:numel(secretLucky)
    if x == secretLucky(i)
        result = true;
    end
end
result
end

[Jacob Boulrice]

Unfortentatly I need to use a for loop. We just learned about them in class so this homework is meant to teach me how to use them.

[Davide Masiello]

I didn't think about that, I have edited my answer accordingly