# binary matrix that has different orders of 0 and 1

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mo on 1 Jan 2015
Edited: Shoaibur Rahman on 1 Jan 2015
I would like to make a binary matrix such that each row has different order of 0 and 1.
For instance if the matrix has 2 columns then it would be 2^2 aspects (4 rows) then the matrix should be as below:
[1 1;
0 1;
1 0;
0 0]
Then if there are 3 columns, there will be 2^3 (=8) rows, and each row should have different orders of 0 and 1 like below:
[1 1 1;
0 0 1;
1 0 0;
0 1 0;
1 1 0;
1 0 1;
0 1 1;
0 0 0]
Can anybody help me to make this matrix?
Roger Stafford on 1 Jan 2015
It isn't clear how the ordering of your rows generalizes for an arbitrary power of 2. Please explain its logic or give many more examples. If the ordering is to be random, please say so.

Azzi Abdelmalek on 1 Jan 2015
Edited: Azzi Abdelmalek on 1 Jan 2015
n=3
out=dec2bin(0:2^n-1,n)
%or
out=dec2bin(0:2^n-1,n)-'0'
Image Analyst on 1 Jan 2015
This is a character array and he wants binary, which might mean logical data type, or maybe integer or even double. Can you show how to make those other data types (logical, int32, double) from these strings?

Shoaibur Rahman on 1 Jan 2015
Edited: Shoaibur Rahman on 1 Jan 2015
If the ordering of rows is not a concern, then use:
n = 3;
A = dec2bin(0:2^n-1);
B = double(A)-48
Note: 48 is the char to double conversion base for 0.

Pourya Alinezhad on 1 Jan 2015
hi, you can easily construct the matrix using:
A=zeros(size^2,size)
where "size" is column number of the matrix. then in order to fill it you can use "Gray" codes. google "Gray code" for more info.
Roger Stafford on 1 Jan 2015
That isn't gray code. Gray code changes only one bit with each step, and in Mo's three-column example, that isn't the case.