Adjacent Repeat of Numbers in an Array

This is the current function

function adjacentRepeat = HasAdjacentRepeat(inArray)
    for inArray=diff(inArray)
        adjacentRepeat=1;

    end

It works to satisfy the following requirements:

• Check for the use of a loop.
• Assessment result: correctCheck adjacentRepeat = 1 for inArray = [2 1 3 3 4 2 5].
• Assessment result: correctCheck adjacentRepeat = 1 for inArray = [4 5 7 6 3 8 9 7 2 8 9 7 3 3 3 7 1].
• Assessment result: correctCheck for correct adjacentRepeat for an array of randomized size and values.

But not for this requirement:

• Assessment result: incorrectCheck adjacentRepeat = 0 for inArray = [1 2 1 2 1].

Answer 1

[Image Analyst]

You never set adjacentRepeat to 0, EVER. So of course it doesn't work.

Did you try just going through your difference array checking if any are 0? If they are, then the adjacent values are the same and you can set the variable and exit.

function adjacentRepeat = HasAdjacentRepeat(inArray)
adjacentRepeat = 0;
d = diff(inArray);
for k = 1 : length(d)
    if d(k) == 0
        adjacentRepeat = 1;
        return;
    end
end
end

[Olivia Rose]

I attempted setting it to 0 and it wasn't working. Thank you for your help.

[Jacob]

I realized the problem I was having is I didnt understand what was or how to use diff. Thank you, this worked perfectly!

Answer 2

[Image Analyst]

Why do you have a for loop? Why not simply do this:

adjacentRepeat = HasAdjacentRepeat([2 1 3 3 4 2 5])
adjacentRepeat = HasAdjacentRepeat([4 5 7 6 3 8 9 7 2 8 9 7 3 3 3 7 1])
adjacentRepeat = HasAdjacentRepeat([1 2 1 2 1])

function adjacentRepeat = HasAdjacentRepeat(inArray)
    adjacentRepeat = any(diff(inArray) == 0);
end

[Olivia Rose]

It has to have a for loop