Display mutiple lines in Text area in Matlab App designer

I have attached my code below.

for a = 1:length(my_Files)
    baseFileName1 = my_Files(a).name;
    fullFileName1 = fullfile(myDir, baseFileName1);
    i = imread(fullFileName1);
    if max(max(i)) == 255
        char6 = sprintf('%s has the presence of tumour \n',baseFileName1);
        app.TextArea3.Value = char6;
        c=c+1;
    end
end
            

I want the text area to display multiple lines like,

Image 1 has the presence of tumour

Image 2 has the presence of tumour

Image 3 has the presence of tumour

Image 4 has the presence of tumour .......

But I get only the last image name in the text area and i coudnt get all the image names as multiple lines.

Image 127 has the presence of tumour

I need someone's help to sort this out.

Thanks in advance.

[Monica Roberts]

Have you tried any of the things in this other post: https://www.mathworks.com/matlabcentral/answers/436084-how-to-display-multiple-lines-as-output-from-code-in-edit-text-field-in-app-designer

[Rik]

Comment posted as answer by @Emerson Nithiyaraj:

@Monica Roberts

I have tried many such suggestions and still I coudnt sort this out.

[Rik]

@Emerson Nithiyaraj

What edits have you tried on your posted code after seeing my answer?

[Emerson Nithiyaraj]

@Rik

            for a = 1:length(my_Files)
                baseFileName1 = my_Files(a).name;
                fullFileName1 = fullfile(myDir, baseFileName1);
                i = imread(fullFileName1);
                char6 = {};
                if max(max(i)) == 255
                    char6{a,1} = char(sprintf('%s has the presence of tumour \n',baseFileName1));
                    app.TextArea3.Value = char6;
                    c=c+1;
                end
            end
            

Still I get an error, Error using matlab.ui.control.TextArea/set.Value (line 109) 'Value' must be a character vector, or a 1-D array of the following type: cell array of character vectors, string, or categorical.

[Monica Roberts]

I see 2 problems here. 1. You are clearing out char6 on every loop iteration. 2. If a is greater than 1, char6 has a bunch of empty cells. To see what I mean, try this code in the command window:

temp{4,1} = 'Example text'

You can make the variable before the for-loop and then tack on text to the end:

char6 = {};
for a = 1:length(my_Files)
    baseFileName1 = my_Files(a).name;
    fullFileName1 = fullfile(myDir, baseFileName1);
    i = imread(fullFileName1);
    if max(max(i)) == 255
        char6{end+1,1} = char(sprintf('%s has the presence of tumour \n',baseFileName1));
        app.TextArea3.Value = char6;
        c=c+1;
    end
end

[Emerson Nithiyaraj]

thank you so much @Monica Roberts. Your sugggestion worked out exactly.

Answer 1

[Rik]

You are replacing the text every iteration. What you need to do is concatenate them.

Start with an empty line before the loop, then append the new results in your loop.

Edit:

for a = 1:numel(my_Files)
    baseFileName1 = my_Files(a).name;
    fullFileName1 = fullfile(myDir, baseFileName1);
    im = imread(fullFileName1);
    char6 = '';
    if max(im(:)) == 255
        if isempty(char6)
            char6 = sprintf('%s has the presence of tumour',baseFileName1);
        else
            char6 = sprintf('%s\n%s has the presence of tumour',char6,baseFileName1);
        end
        app.TextArea3.Value = char6;
        c=c+1;
    end
end

[Emerson Nithiyaraj]

I tried this but, I still get only the last image name in the text area. I didnt get multiple image names in the text area.

[Rik]

You can also use a cellstr instead of a char vector:

for a = 1:numel(my_Files)
    baseFileName1 = my_Files(a).name;
    fullFileName1 = fullfile(myDir, baseFileName1);
    im = imread(fullFileName1);
    char6 = '';
    if max(im(:)) == 255
        if isempty(char6)
            char6 = {sprintf('%s has the presence of tumour',baseFileName1)};
        else
            char6{end+1,1} = sprintf('%s\n%s has the presence of tumour',char6,baseFileName1);
        end
        app.TextArea3.Value = char6;
        c=c+1;
    end
end