Splitting columns based on comma

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Hey everyone, I have a table (raw) with several columns, one of them is 'Position' (see below) which contains different coordinates. Some rows are blank (''). I want to split the coordinates based on the comma between them and put them seperately back to the 'raw' table.
raw.Position =
''
''
''
'(-6.9, 4.8, 68.4)'
'(-8.5, 3.1, 18.0)'
'(13.5, 2.5, 70.1)'
''
''
I tried the following
P = raw.Position
new = regexp(P, ',','split');
raw.a = P(:,1); Error: Index in position 2 exceeds array bounds. Index must not exceed 1.
raw.b = P (:,2);
raw.c = P (:,3);
but the 'new' table saved the splitted coordinates in 1x3 cells, so they could not be transfered back to the 'raw' table (I think that's the problem). Also, I wanted to remove the brackets as well from the coordinates which did not work either.. Any help appreciated!
new =
''
''
''
1x3 cell
1x3 cell
1x3 cell
''
''

Accepted Answer

Stephen23
Stephen23 on 1 Jun 2022
raw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''};
tmp = sscanf(sprintf('%s',raw.Position{:}),'(%f,%f,%f)',[3,Inf]).';
raw.a = tmp(:,1);
raw.b = tmp(:,2);
raw.c = tmp(:,3)
raw = struct with fields:
Position: {8×1 cell} a: [3×1 double] b: [3×1 double] c: [3×1 double]
  3 Comments
Stephen23
Stephen23 on 3 Jun 2022
aw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''};
fnh = @(t) sscanf(t,'(%f,%f,%f)',[1,3]);
V = cellfun(fnh,aw.Position,'uni',0);
V(cellfun(@isempty,V)) = {nan(1,3)};
M = vertcat(V{:})
M = 8×3
NaN NaN NaN NaN NaN NaN NaN NaN NaN -6.9000 4.8000 68.4000 -8.5000 3.1000 18.0000 13.5000 2.5000 70.1000 NaN NaN NaN NaN NaN NaN

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More Answers (2)

greenyellow22
greenyellow22 on 3 Jun 2022
But with that I would end up having the coordinates in one column all together again, and not have them splitted into three columns... :/

greenyellow22
greenyellow22 on 3 Jun 2022
Thanks!
Instead of aw.Position = {'';'';'';'(-6.9, 4.8, 68.4)';'(-8.5, 3.1, 18.0)';'(13.5, 2.5, 70.1)';'';''}, I wrote
XY = aw.Position;
fnh = @(t) sscanf(t,'(%f,%f,%f)',[1,3]);
V = cellfun(fnh,XY,'uni',0);
V(cellfun(@isempty,V)) = {nan(1,3)};
M = vertcat(V{:})
(aw is a table already existing, where Position is just one column with more rows and coordinates than the example I gave).
but then I get the error message:
Error using vertcat
Dimensions of arrays being concatenated are not consistent.
I'm sorry, I just don't have enough transfer knowledge to adapt your commands accordingly.
  4 Comments
greenyellow22
greenyellow22 on 6 Jun 2022
I understand but unfortunately, I cannot upload the data. But I have a table of 5 columns and one column contains the coordinates (23420x1 cells), whereby some cells/ rows are empty and some contain the coordinates (e.g. '(-6.9, 4.8, 68.4)'). So for all cells containing coordinates I want to split the coordinates into three and enter these seperately into three different new columns added to the table (with the empty cells staying empty). If writing the commands is impossible without the data, then I understand and thank you anyway for your prior help :-)

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