If statement working partially

2 views (last 30 days)
Gonzalo Guerrero
Gonzalo Guerrero on 21 Jun 2022
Commented: Voss on 22 Jun 2022
Hi,
I have been havin problems with the following if statment. My data loads in a loop, which will run depending on the if statment. When it comes to the elseif everything run very smoothly, however, when it comes to the if conditions, it doesn't. I tried to put a keyboard afterwards, because the Time variable gave me error, although once the keyboard is placed, I can put the whole if statment and it will work. As soon as i press continue, it doesn't.
Could you help, please? :D
Thank you
while n<=length(DigMark.codes)
if n==length(DigMark.codes)+1
break;
end
while nn<=4
if n==length(DigMark.codes)+1
break;
end
if nn==4
n=n+1;
nn=1;
continue;
end
if DigMark.codes (n) == 65 || DigMark.codes(n)== 67 || DigMark.codes(n)== 68 ||...
DigMark.codes(n)== 69 && DigMark.codes(n+1)~= 88
Times = find(EMG{nn}.times > DigMark.times(n)-.0004& EMG{nn}.times < DigMark.times(n)+.0004);
Times=Times(1);
Time=EMG{nn}.times(Times);
Code= DigMark.codes(n);
ValuesEMG=(EMG{nn}.values(Times:Times+316));
CalibrateEMG=(0-mean(EMG{nn}.values(Times-316:Times)));
ValuesEMG=(ValuesEMG+CalibrateEMG);
P2PEMG= max(ValuesEMG(48:179))-min(ValuesEMG(48:179));
RMSEMG=rms(EMG{nn}.values(Times-316:Times));
.
.
.
nn=n+1;
elseif DigMark.codes(n)==66 || DigMark.codes(n)== 70 || DigMark.codes(n)== 71 && DigMark.codes(n+1)~= 88
times = find(EMG{nn}.times > DigMark.times(n)-.0004& EMG{nn}.times < DigMark.times(n)+.0004);
times=times(1);
Time=EMG{nn}.times(times);
Code= DigMark.codes(n);
ValuesEMG=(EMG{nn}.values(times:times+161));
CalibrateEMG=(0-mean(EMG{nn}.values(times-314:times)));
ValuesEMG=(ValuesEMG+CalibrateEMG);
P2PEMG= max(ValuesEMG(16:end))-min(ValuesEMG(16:end));
RMSEMG=rms(EMG{nn}.values(times-316:times));
.
.
.
nn=nn+1;
else
n=n+1;
nn=1;
end
end
end
  1 Comment
Stephen23
Stephen23 on 22 Jun 2022
Replace
x == 65 || x == 67 || x == 68 || x == 69 && y ~= 88
with
ismember(x,[65,67:69]) && y ~= 88

Sign in to comment.

Answers (1)

Voss
Voss on 21 Jun 2022
Part of the problem might be the usage of || and &&.
In MATLAB, && takes precedence over ||, so an expression like this:
x == 65 || x == 67 || x == 68 || x == 69 && y ~= 88
is interpreted as this:
x == 65 || x == 67 || x == 68 || (x == 69 && y ~= 88)
but I think you probably mean this:
(x == 65 || x == 67 || x == 68 || x == 69) && y ~= 88
Here's a concrete case where it makes a difference:
x = 65;
y = 88;
disp( x == 65 || x == 67 || x == 68 || x == 69 && y ~= 88 )
1
disp( (x == 65 || x == 67 || x == 68 || x == 69) && y ~= 88 )
0
Another potential problem is that you let n go up to length(DigMark.codes) but then try to access DigMark.codes(n+1).
  2 Comments
Gonzalo Guerrero
Gonzalo Guerrero on 22 Jun 2022
Thanks for your answer!
I considered that too, but It is weird that the line of elseif works, but then the if doesn't...
I have changed the while loop for a for loop instead and now it works perfectly. It might be just the loop wasn't the right one, for some reason I don't know :S
Voss
Voss on 22 Jun 2022
I don't think either line (if or elseif) was working as you probably intended. Maybe the elseif appeared to work for whatever values it happened to get.

Sign in to comment.

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!