Disturbance Rejection with PID turner

I'm trying to do a disturbance rejection with PID tuner.I'm trying to do it but it keeps giving error.Could you help me?
G=tf([1],[0.1 1]);
G.InputName='yzad';
G.Output='ys';
yzad={1,10,100}
K={-100,-10,1,5,3}
Sum=sumbkl('++','yzad','ys')
ISAPID=connect('-100','Sum','G')
tf(ISAPID)
You can find my diagram attached .Thanks

 Accepted Answer

For simplicity, you can do something straightforward and plot the time responses like this.
Case 1a: , rad/s
% sin(omega*t) = sin((2π*Freq)*t) = sin((2π/τ)*t)
omega = 1; % angular frequency {1, 10, 100} rad/s
tau = 2*pi/omega; % time period of a wave
Tf = 2*tau; % wave duration of Tf seconds
[u, t] = gensig("sine", tau, Tf); % generates a signal where t runs from 0 to Tf seconds
G = tf(1, [0.1 1]); % plant transfer function
K = -100; % feedback gain {-100, -10, -1, 5, 3}
H = -K;
Gcl = feedback(G, H) % closed-loop system subjected to a disturbance Y(s)/D(s)
Gcl = 1 ----------- 0.1 s + 101 Continuous-time transfer function.
lsim(Gcl, u, t)
grid on
Case 1b: , rad/s
% sin(omega*t) = sin((2π*Freq)*t) = sin((2π/τ)*t)
omega = 10; % angular frequency {1, 10, 100} rad/s
tau = 2*pi/omega; % time period of a wave
Tf = 2*tau; % wave duration of Tf seconds
[u, t] = gensig("sine", tau, Tf); % generates a signal where t runs from 0 to Tf seconds
G = tf(1, [0.1 1]); % plant transfer function
K = -100; % feedback gain {-100, -10, -1, 5, 3}
H = -K;
Gcl = feedback(G, H) % closed-loop system subjected to a disturbance Y(s)/D(s)
Gcl = 1 ----------- 0.1 s + 101 Continuous-time transfer function.
lsim(Gcl, u, t)
grid on
Case 1c: , rad/s
% sin(omega*t) = sin((2π*Freq)*t) = sin((2π/τ)*t)
omega = 100; % angular frequency {1, 10, 100} rad/s
tau = 2*pi/omega; % time period of a wave
Tf = 2*tau; % wave duration of Tf seconds
[u, t] = gensig("sine", tau, Tf); % generates a signal where t runs from 0 to Tf seconds
G = tf(1, [0.1 1]); % plant transfer function
K = -100; % feedback gain {-100, -10, -1, 5, 3}
H = -K;
Gcl = feedback(G, H) % closed-loop system subjected to a disturbance Y(s)/D(s)
Gcl = 1 ----------- 0.1 s + 101 Continuous-time transfer function.
lsim(Gcl, u, t)
grid on
Case 2a: , rad/s
% sin(omega*t) = sin((2π*Freq)*t) = sin((2π/τ)*t)
omega = 1; % angular frequency {1, 10, 100} rad/s
tau = 2*pi/omega; % time period of a wave
Tf = 2*tau; % wave duration of Tf seconds
[u, t] = gensig("sine", tau, Tf); % generates a signal where t runs from 0 to Tf seconds
G = tf(1, [0.1 1]); % plant transfer function
K = -10; % feedback gain {-100, -10, -1, 5, 3}
H = -K;
Gcl = feedback(G, H) % closed-loop system subjected to a disturbance Y(s)/D(s)
Gcl = 1 ---------- 0.1 s + 11 Continuous-time transfer function.
lsim(Gcl, u, t)
grid on

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on 25 Jun 2022

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on 25 Jun 2022

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