how can i find more than one minimum points of the histogram??

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user06
user06 on 5 Feb 2015
Commented: Image Analyst on 21 Feb 2015
Suppose I have a histogram and I want to find the minimum point of the histogram other than 0, then what procedure I should follow? In the histogram image below, the minimum point is approximately 10,15,17. Then how can I find this?

Answers (2)

Image Analyst
Image Analyst on 5 Feb 2015
Try this
% Get histogram
[pixelCounts, grayLevels] = imhist(grayImage);
% Find darkest bin with more than 15 pixels in it
darkestGL = find(pixelCounts > 15, 1, 'first');
  36 Comments
user06
user06 on 20 Feb 2015
and the code u have given is just giving the first 3 minimum points. i want overall 3 minimum points

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Jos (10584)
Jos (10584) on 17 Feb 2015
You can sort the outcome of the histogram
data = ceil(10*rand(100,1))
values = 1:10
count = histc(data,values)
[SortedCount, idx] = sort(count)
SortedValues = values(idx)
disp([SortedValues(:) SortedCount(:)])
  6 Comments
Image Analyst
Image Analyst on 21 Feb 2015
I did that in my code above. Like I said, "the lowest bin has one count in it and it occurs at bin 236. The second lowest bin also has only one pixel in it, and it occurs at gray level 237, and the third lowest bin also has only one count in it and it occurs at 247." Explain why 1 is not the lowest y value (count in the bin), and explain why 236,237,247 is not sorted.

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