how to multiply a number to matrix?

Hello everyone,
I have a matrix 180X360X1332 (Latitude X Longitude X Time). I want to multiply 30 at every fourth number of third demension (e.g., 1,5,9,13......1332)
I have tried this for vector data:
Y = 30*(1:4:1332);
How can I do this for matrix data?
Thanks

3 Comments

"a number 30 in time demension at interval of 4"
Not sure someone can understand this.
@Bruno Luong I have updated my question. Hope this is clear now.
If that is the case, see @vishweshwar samba answer

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 Accepted Answer

I assume that the matrix 180X360X1332 (Latitude X Longitude X Time) is a multidimentional array and you want to multiply a value of 30 to (Latitude X Longitude) in the interval of 4 wrt Time.
% By using the below for loop, created a matrix 'A' of dimension 180x360x1332 (Latitude X Longitude X Time)
for i = 1:1332
A(:,:,i) = ones(180,360);
end
% Now multiply a number 30 in time dimension at interval of 4(1:4:1332)
A(:,:,1:4:1332) = A(:,:,1:4:1332)*30;

8 Comments

@vishweshwar samba @Bruno Luong I have tried this but not working
for i = 1:1332,
x = data(:,:,i);
y = x(:,:,1:4:1332)*30;
z(:,:,i) = y;
end;
here the third dimension is rainfall data for 1332, so I want to multiply a value of 30 to rainfall data.
Remove the for-loop, just
data(:,:,1:4:end) = data(:,:,1:4:end)*30;
I dont understand why you are using for loop. Instead replace your code with the code mentioned below.
data(:,:,1:4:1332) = data(:,:,1:4:1332)*30;
If you prefer for-loop
z = data;
for i = 1:4:size(z,3)
z(:,:,i) = z(:,:,i)*30;
end
I have one more question in this regard, suppose, I have a time series (1x48) and I want to extract values at particular interval. Means, I want to creat a new time series which will have only 12 values. e.g., 1,5,9,13,17, 21, 25, 29, 33, 37, 41, 45
How can I do this?
Thanks
@Aarti Soni I suggest you to create a new thread and better description. Someone else can answer to you.

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