How to programatically select nodes of an uitree in AppDesigner?

Hi,

I would like to programatically select nodes of a an uitree in AppDesigner. I have

And would like to select all nodes with the Tag "Image". (I alreade have set this Tag during creating the tree).

Answer 1

[Kevin Holly]

Ron,

Please see the app attached.

The callback in attach app is:

  function ButtonPushed(app, event)
            app.Node.Tag = 'Image';
            app.Node4.Tag = 'Image';
            app.Node_3.Tag = 'Image';

            for ii = 1:length(app.Tree.Children)
%                 if strcmp(app.Tree.Children(ii).Tag,'Image')
%                     app.Tree.CheckedNodes = [app.Tree.CheckedNodes; app.Tree.Children(ii)];
%                 end
                for jj = 1:length(app.Tree.Children(ii).Children)
                    if strcmp(app.Tree.Children(ii).Children(jj).Tag,'Image')
                        app.Tree.CheckedNodes = [app.Tree.CheckedNodes; app.Tree.Children(ii).Children(jj)];
                    end
                    for kk = 1:length(app.Tree.Children(ii).Children(jj).Children)
                        if strcmp(app.Tree.Children(ii).Children(jj).Children(kk).Tag,'Image')
                            app.Tree.CheckedNodes = [app.Tree.CheckedNodes; app.Tree.Children(ii).Children(jj).Children(kk)];
                        end
                    end
                end
            end 
  end
  
  

If you wanted to just select 2nd layer of nodes, you could do the folllowing:

  
            for ii = 1:length(app.Tree.Children)
                for jj = 1:length(app.Tree.Children(ii).Children)
                    if strcmp(app.Tree.Children(ii).Children(jj).Tag,'Image')
                        app.Tree.CheckedNodes = [app.Tree.CheckedNodes; app.Tree.Children(ii).Children(jj)];
                    end
                end
            end

[Ron Hoebe]

Dear Kevin,

Thanks, with a little modification it works. I wanted to select them, (not check them). The code below is perfect for me.

Best, Ron

app.Tree.SelectedNodes=[];

for ii = 1:length(app.Tree.Children)

for jj = 1:length(app.Tree.Children(ii).Children)

if strcmp(app.Tree.Children(ii).Children(jj).Tag,'Image')

app.Tree.SelectedNodes = [app.Tree.SelectedNodes; app.Tree.Children(ii).Children(jj)];

end

for kk = 1:length(app.Tree.Children(ii).Children(jj).Children)

if strcmp(app.Tree.Children(ii).Children(jj).Children(kk).Tag,'Image')

app.Tree.SelectedNodes = [app.Tree.SelectedNodes; app.Tree.Children(ii).Children(jj).Children(kk)];

end

end

end

end

Answer 2

[Cris LaPierre]

You can use app.Tree.SelectedNodes

I found this example helpful. There will need to be some modifications to get it to work inside an app. You could use the names of the nodes to select, but that gets cumbersome with the names you use.

app.Tree.SelectedNodes = [app.C1tifNode]

I find it easier to use the tree structure to select multiple nodes (note you must turn Multiselect on. Select the tree in your component browser and expand the interactivity property). For example, this code selects the 2nd and 3rd child nodes under the 2nd node.

app.Tree.SelectedNodes = app.Tree.Children(2).Children(2:3);

For your final question on using the Tag property to select nodes, the only way I could find to do this was to loop through each node. I don't love this solution, but it works.

nodes = [];
for n = 1:length(app.Tree.Children)
    for n1 = 1:length(app.Tree.Children(n).Children)
        if strcmp(app.Tree.Children(n).Children(n1).Tag,'image')
            nodes = [nodes app.Tree.Children(n).Children(n1)];
        end
    end
end
app.Tree.SelectedNodes = nodes

[Cris LaPierre]

I see you got an answer while I was working on mine. I'll leave it in case it is helpful.

[Ron Hoebe]

Hi Cris,

Thanks for alle the examples. The TAG Property is very handy for me to select nodes. So Kevin's answer and your last example are perfect for me.

Best,Ron