Finding the turning point on a curve

Hello;

I have a question about finding the turning points on a graph. See the curve that is attached. Its basically a second derivate of the data, and I can see the maximum values (points of interests) at x=10, x=37. How can I automatically find those two indices for these two maximum points.

The input data is also attached.

Answer 1

[Torsten]

v = [-0.000499915992890149
    -0.00136716055731299
    -0.00312202879147695
    -0.00415143850349407
    -0.00372399579905874
    -0.00214247189597304
    -4.88031918734373e-05
    0.00186090040637454
    0.00310143550393687
    0.00352174551809843
    0.00326203341992525
    0.00261014952275744
    0.00185224852020417
    0.00118261260181092
    0.000685142369381347
    0.000361685775221777
    0.000173644481175180
    7.45001399801368e-05
    2.65154258571087e-05
    4.92923050407924e-06
    -4.18585620462963e-06
    -7.66464037567534e-06
    -8.27292576250456e-06
    -6.40533966605236e-06
    -5.74990859836169e-07
    1.30721733050333e-05
    4.20520793933117e-05
    9.94354287544991e-05
    0.000205809520089438
    0.000390149987664096
    0.000687660786704286
    0.00113216341113945
    0.00174119870531302
    0.00249441537474893
    0.00331021806888304
    0.00403084496564659
    0.00442921778777076
    0.00424844768230841
    0.00327454998785455
    0.00169124545504720
    0.000814499263465100];
[pks,locs] = findpeaks(v)

pks = 2×1

0.0035 0.0044

locs = 2×1

10 37

[Muhammad Ghani]

Great. Thank you