How do i count numbers ending in 3
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I have a bunch of numbers x=[234 352 298 213 365 321 293 213], Iwant to know how to count number ending in 3. The output should be 3
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Answers (3)
Torsten
on 26 Aug 2022
x = [234 352 298 213 365 321 293 213];
n = numel(x);
end_digit = zeros(n,1);
for i = 1:n
y = num2str(x(i));
end_digit(i) = str2num(y(end));
end
s = sum(end_digit==3)
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Abderrahim. B
on 26 Aug 2022
This:
x =[234 352 298 213 365 321 293 213] ;
xs = strsplit(num2str(x), ' ') ;
total = nnz(endsWith(xs, '3'))
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Stephen23
on 26 Aug 2022
Simple, efficient, basic mathematics:
x = [234,352,298,213,365,321,293,213];
n = nnz(mod(x,10)==3)
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