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How to use the simulation time in an embedded function in matlab

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Dear matlabers,
I am wondering how to correct this simple code in a matlab embedded function included in a simulink file.
function y= hybrid(t, dpo, dic)
if t < 0.04762
In this simple code, "t" would be the simulation time and it is obtained by means of a clock block. However, when I try to compile it, matlab console reports the following error:
"This assignment writes a 'double' value into a 'logical' type. Code generation does not support changing types through assignment. Check preceding assignments or input type specifications for type mismatches. Function 'Hybrid Algorithm/MPPT P&O Function' (#146.60.61), line 6, column 1: "y""
How can I make this simple function work?I have searched for similar questions and applied several advices but with no success.
Thanks a lot.
  1 Comment
dpb on 1 Oct 2022
What are dpo, dic data types and what is the target to which you're trying to assign the result?
I don't know anything at all about Simulink, but my reading says the error says your function needs to return a logical value, not a numeric one.
But, if the two arguments other than t are numeric, then "you can't do that!" because the y value will have to be numeric to hold those values.
What your function could do with these inputs wouldn't have any bearing on what the values of the other two arguments are; but simply return the logic flag
function y= hybrid(t)
and then you'd need some way to use that result to switch the two inputs to wherever they're supposed to be going.
But, folks would have to see the pertinent parts of the model to have any idea about the total solution.

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Accepted Answer

Walter Roberson
Walter Roberson on 1 Oct 2022
You are calling hybrid() in a context where through propagation or backwards propagation or explicit setting in the block, or by assignment to the output variable before calling the function... that Simulink has determined that the function is being used in a situation in which the output must be logical but you are returning double instead.
You need to analyze the context in which the function is being called to determine why Simulink thinks the output must be logical.

More Answers (1)

Manyu Hati
Manyu Hati on 2 Oct 2022
Edited: Manyu Hati on 2 Oct 2022
Hi guys,
Thank you for the valuable comments. It seems that the "embedded matlab function block" only treats well numerical variables, but not logical ones. In my specific problem, logical outputs were necessary. However, I managed to treat the variables in the numerical domain by means of this embedded matlab function. After that, I converted them into the logical domain. And in this way, it finally worked!


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