I am beginner in matlab, and i struggly to resolve some exercice. can I have some advice according to this task?
1-1/3+1/5-1/7+1/9-..-1/1003

 Accepted Answer

n=1:502;
s=sum((-1).^(n+1)./(2*n-1))
s = 0.7849

7 Comments

how did you get 502 for the loop
VBBV
VBBV on 29 Oct 2022
The highest term in the fraction of series is 1003. So it can obtained by this way 2*502-1
2*502 -1 = 1003 (last element). 2*n-1 is an expression for odd numbers.
This cod are not working
>> a = 1;
k = 502;
for x = 1:k
s = sum(((-1).^(x+1))./(2*(x-1)));
end
disp(s)
-9.9800e-04
No need for a loop. Just run the below code.
x=1:502;
s=sum((-1).^(x+1)./(2*x-1))
s = 0.7849
Maybe of interest:
syms n
s = simplify(symsum((-1)^n/(2*n+1),0,Inf))
s = 
I get it!
Thank you very much!

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