Plotting a given function over an interval

I am given the following function:

f(x) = x^5 - 6.13x^2 - 0.83x - (0.62 / (x^2 + 0.0825)) + 5.2

and I am wanting to plot this function over an interval from -1.5 to 1.5 to determine the roots of this function but whenever I try to plot the function using the following:

x1 = -1.5 : 0.1 : 1.5;

y1 = (x.^5) - (6.13*x.^2) - (0.83*x) - (0.62 ./ (x.^2 + 0.0825)) + 5.2;

plot(x1,y1);

it errors and says that the 'vector must be the same length' and whenever I am able to get the plot to plot, then it plots a vertical line, whereas the actual function has 4 different zeros along the given interval. Please help....

[Jordan]

I've also tried using the 'fplot' command and the command itself errors out with a bunch of underlying errors as well.

Answer 1

[VBBV]

syms x
y1 = (x.^5) - (6.13*x.^2) - (0.83*x) - (0.62 ./ (x.^2 + 0.0825)) + 5.2;
fplot(y1,[-1.5 1.5])  % range of values 

[VBBV]

x1 = -1.5 : 0.1 : 1.5;
y1 = @(x) (x.^5) - (6.13*x.^2) - (0.83*x) - (0.62 ./ (x.^2 + 0.0825)) + 5.2; % without symbolic variables
plot(x1,y1(x1));  

you can use anonymous function to plot graph or use symbolic variables and graoh using fplot