怎样把一个自定义函数​曲线当作信号源输入s​imulink中。

如何把下面这个五次多项式曲线函数(函数自变量xr是有区间范围的变量)当作信号源作为simulink的输入?请大神指点
xr=0.972:0.2:8.443805773200967;
format long
k1=2.769816862072388e-04;
k2=-0.005610355231804;
k3=0.026843559416301;
k4=0.052552706368628;
k5=-0.158874118883267;
k6=-0.784608978245300;
yr=k1*xr.^5+k2*xr.^4+k3*xr.^3+ k4*xr.^2+k5*xr+k6;%后轴中心点坐标运行轨迹

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on 17 Nov 2022

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