Function inside a for loop

1 view (last 30 days)
gdz
gdz on 17 Dec 2022
Moved: Walter Roberson on 18 Dec 2022
Hi,
I have a function that works well when I called it one by one.
>>Calculate(a,cs,sclk)
ans: 20
>>Calculate(a,cs,sclk)
ans: 20.5
>>Calculate(a,cs,sclk)
ans: 20.25
However, when i switching the function inside a for loop, it kept produced the same answer.
for j=1:9
d=Calculate(a,cs,sclk);
fprintf('value %d is %d\n',j,d);
end
Asnwer:
value 1 is 10
value 2 is 10
.
.
.
value 9 is 10
And I called it in a series. They all produced the same answer.
>> d1=Calculate(a,cs,sclk);d2=Calculate(a,cs,sclk);d3=Calculate(a,cs,sclk);d4=Calculate(a,cs,sclk);
Ans:d1=15,d2=15,d3=15,d4=15,d5=15
Anyone know what's happened for my function here?
  4 Comments
Askic V
Askic V on 17 Dec 2022
You can measure time with tic and toc.
Please have a look at:
https://www.mathworks.com/help/matlab/ref/tic.html
gdz
gdz on 18 Dec 2022
Thank you all of your help

Sign in to comment.

Accepted Answer

Askic V
Askic V on 17 Dec 2022
Moved: Walter Roberson on 18 Dec 2022
For loop will be executed in a matter of milliseconds. On the other hand when you call function once at a time, there is a significantly more time difference between calls. So perhaps your input parameters cannot change fast enough in the loop call.
  2 Comments
Walter Roberson
Walter Roberson on 17 Dec 2022
Moved: Walter Roberson on 18 Dec 2022
I agree with Askic V
gdz
gdz on 17 Dec 2022
Moved: Walter Roberson on 18 Dec 2022
I have add a pause function inside and it works!!!! Thank you very much.

Sign in to comment.

More Answers (0)

Categories

Find more on Loops and Conditional Statements in Help Center and File Exchange

Products


Release

R2020a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!