Keep pairs of corresponding elements in 2 vectors based on conditions
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I have the problem here: Using this image below: I want to check for several conditions
the orange and green marks are annotations on a signal. If we consider vectors orange, and green which contain the points needed to make the annotations.
The point is to have perfect pairs and ignore all others. i.e. orange(i) and green(i) is a pair if orange(i)<green(i)
so all values in vector orange are lower than their corresponding elements in vector green.
I want to check the following conditions.
I started but some conditions dont work, thats why i need help.
Condition 1: orange must always begin, so if a green begins I delete that green point. [done]
condition 2: if 2 or more greens come before an orange, delete all unecessary green to keep a pair.
condition 3: similarly if several orange exist delete them to keep a pair.
so in the end I want to have a perfect system of pairs, where orange starts a pair. like this:
i = 1;
while i <= lenss
if abs(green(i)-orange(i)) <0
green(i) = ;
Jan on 14 Mar 2023
Edited: Jan on 14 Mar 2023
orange = [212929;213223;213482;213740;214013;214790];
green = [212765;213301;213822;214090;214240;214426;214941];
[x, s] = sort([orange.', green.']);
index = strfind(s <= numel(orange), [true, false]);
ok_orange = x(index)
ok_green = x(index + 1)
The idea: sort all elements. If their sorting index is greater than the number of orange elements, they are green. So s <= numel(orange) is a logical vector, which is TRUE for orange and FALSE for green. Now find the neighboring [true, false] pairs.
Kind regards to @Bruno Luong, who told me this method over 20 years ago. :-)