Solving a complicated system of ODEs
Show older comments
I'm trying to numerically solve a set of differential equations by using ode45 (I don't know if this is the most appropriate one). My code is below. The annoying thing is that this seems to run but gives invalid solutions. Also, the k parameter should be a variable, not a parameter with a specific value. I don't know how to implement this. It is certainly possible that my initial conditions are incorrect, however, this shouldn't really have an impact if the code runs or not I think.
I'm not fluent at all with this syntax, so bare with me for not understanding everything.
EDIT: I've added the problem I am solving below. Note that the transfer function depends on k and can be obtained through δ I believe. I'll have to check this.

clear; clc;
sol = ode45(@ode_fun, [0 1], [1; 0; 0; 0; 0; 1]);
function dydt = ode_fun(t, y)
rhodm = 0.8;
rho = 1.0;
G = 0.000000000066743;
H0 = 1; %Model dependent?
Omr = 0.0000463501;
Omm = 0.2514;
Omk = 0;
OmLa = 0.6847;
k=1.0;
theta0 = y(1);
theta1 = y(2);
Phi = y(3);
delta = y(4);
v = y(5);
a = y(6);
dydt = zeros(size(y));
dydt(1) = -dydt(5) - k.*theta1;
dydt(2) = -k./3.*(Phi-theta0);
dydt(3) = -3.*dydt(5) - 1i.*k.*v;
dydt(4) = 1i.*k.*Phi - dydt(6)/a.*v;
dydt(5) = (4.*pi.*G.*a.^2.*(rhodm.*delta + 4.*rho.*theta0) - k.^2.*Phi ).*a/(3.*dydt(6)) - dydt(6)/a.*Phi;
dydt(6) = H0 * a .* sqrt(Omr ./ a.^4 + Omm ./ a.^3 + Omk ./ a.^2 + OmLa);
end
3 Comments
James Tursa
on 12 May 2023
Edited: James Tursa
on 12 May 2023
Please post an image/pic of the differential equations you are solving. If k is supposed to be a variable, what are the differential equations governing it? Why isn't it one of your y elements?
bozo
on 12 May 2023
Answers (1)
Torsten
on 11 May 2023
You use dydt(5) and dydt(6) before they have been assigned their values:
dydt(1) = -dydt(5) - k.*theta1;
dydt(2) = -k./3.*(Phi-theta0);
dydt(3) = -3.*dydt(5) - 1i.*k.*v;
dydt(4) = 1i.*k.*Phi - dydt(6)/a.*v;
dydt(5) = (4.*pi.*G.*a.^2.*(rhodm.*delta + 4.*rho.*theta0) - k.^2.*Phi ).*a/(3.*dydt(6)) - dydt(6)/a.*Phi;
Use instead a modified order in the calculation of the derivatives:
dydt(6) = H0 * a .* sqrt(Omr ./ a.^4 + Omm ./ a.^3 + Omk ./ a.^2 + OmLa);
dydt(5) = (4.*pi.*G.*a.^2.*(rhodm.*delta + 4.*rho.*theta0) - k.^2.*Phi ).*a/(3.*dydt(6)) - dydt(6)/a.*Phi;
dydt(1) = -dydt(5) - k.*theta1;
dydt(2) = -k./3.*(Phi-theta0);
dydt(3) = -3.*dydt(5) - 1i.*k.*v;
dydt(4) = 1i.*k.*Phi - dydt(6)/a.*v;
Categories
Find more on Ordinary Differential Equations in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!