Difference between ar() function burg implementation and arburg() function
Show older comments
If we have e.g. ar(y,20,'Burg') where y is the time series and 20 is the model order, y must have a length of 40 data points minimum to work.
If we have arburg(y,20) y can have a length of 20 data points minimum to work.
Why ar() requires double the data points compared to arburg() for the same model order?
For ar() if model order is 20 and data points are 40, does it consider the 20 last observations and discard the 20 first observations?
Accepted Answer
More Answers (0)
Categories
Find more on Parametric Modeling in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!