Algorithm 1. Set time step (increment) 2. set max number of time steps 3. start with ground values of temperature at x=0, y=0, z=0, theta=0, and a particular value of fi 4. co

% Initialize variables

height = F2007120317S7627.Height;

wind_speed = F2007120317S7627.WS;

wind_direction = F2007120317S7627.WD;

temperature = F2007120317S7627.Temp0;

humidity = F2007120317S7627.HumiS;

min_humid = max(humidity);

theta_limit = 45;

time_limit = 100;

phi_limit = 90;

delta_vx = zeros(101, 1);

delta_vy = zeros(101, 1);

delta_x = zeros(theta_limit, phi_limit);

delta_y = zeros(theta_limit, phi_limit);

delta_z = zeros(theta_limit, phi_limit);

delta_theta = zeros(theta_limit, phi_limit);

x = zeros(theta_limit, phi_limit);

y = zeros(theta_limit, phi_limit);

z = zeros(time_limit, theta_limit); % Fixed dimension

delta_t = 0.1;

theta_end = zeros(theta_limit + 1, phi_limit);

phi = linspace(0, 2 * pi, phi_limit);

theta = linspace(0, pi / 2, theta_limit);

temp1 = 26.3;

delta_t = 1;

vx1 = 0;

vy1 = 0;

alti_matrix = [];

vx = zeros(time_limit, theta_limit);

vy = zeros(time_limit, theta_limit);

cs = zeros(time_limit, theta_limit);

z = zeros(time_limit, theta_limit); % Fixed dimension

cs(1, :) = 331;

for i = 1:theta_limit

delta_z(1, i) = z(1, i) + (cs(1, i) * cos(theta(1, i))) * delta_t;

z(1, i) = delta_z(1, i);

year = z(1, i);

alti_matrix = [alti_matrix, year];

yr = linspace(0, 180, time_limit);

altitude = 0:z(1, i):z(1, i) * 4;

% alt(k,i) = altitude(1,k);

temp1 = spline(height, temperature, altitude);

temp_inv = temp1.';

speed1 = interp1(height, wind_speed, altitude);

speed_inv = speed1.';

dir1 = interp1(height, wind_direction, altitude);

dir_inv = dir1.';

vx(1, i) = speed_inv(1, 1) * cos(deg2rad(dir_inv(1, 1)));

vy(1, i) = speed_inv(1, 1) * sin(deg2rad(dir_inv(1, 1)));

% delta_vx(1,i) = vx(1,i) - vx(1,i);

% delta_vy(1,i) = vy(1,1) - vy(1,i);

humd1 = interp1(height, humidity, altitude);

humd_inv = humd1.';

q(1, i) = humd_inv(1, 1) / min_humid;

temp_kelvin(1, i) = (273.15 + temp_inv(1, 1)) * (1 + 0.608 * q(1, i));

cs(1, i) = 20.047 * sqrt(temp_kelvin(1, i));

% delta_cs(1,i) = cs(k+1,i) - cs(k,i);

end

Answer 1

[Bhavani Sankar]

timeStep = 0.1;

maxTimeSteps = 100;

initialTemperature = 25.0;

initialTheta = 0.0;

initialPhi = 45.0;

deltaTheta = 1.0;

x = 0;

y = 0;

z = 0;

theta = initialTheta;

phi = initialPhi;

temperature = initialTemperature;

temperatureHistory = zeros(maxTimeSteps, 1);

NxHistory = zeros(maxTimeSteps, 1);

NyHistory = zeros(maxTimeSteps, 1);

for t = 1:maxTimeSteps

% Store temperature at current time step

temperatureHistory(t) = temperature;

Nx = sin(theta); % Replace with your calculation

Ny = cos(theta); % Replace with your calculation

NxHistory(t) = Nx;

NyHistory(t) = Ny;

deltaX = 0.1; % Replace with your calculation

deltaY = 0.2; % Replace with your calculation

deltaZ = 0.3; % Replace with your calculation

deltaTheta = 0.1; % Replace with your calculation

x = x + deltaX;

y = y + deltaY;

z = z + deltaZ;

theta = theta + deltaTheta;

interpolatedTemperature = initialTemperature + z * 0.2; % Example interpolation

temperature = interpolatedTemperature;

if z >= someTerminationCondition

break;

end