Symbolic toolbox differentiation by chain rule without expression defined

Hello,

let's say I have variables x and y that depend on time. .

I have a third variable z which is a function of x and y only. .

Here, I do not have any expression that explicitly defines z, but I just know that it is a function of only x and y.

Then, I want to come up with an expression for .

I am expecting to see something like

I thought the code below would do this:

syms x(t) y(t) z(x,y) 
diff(z,t)

ans(x, y) = 

0

but it is just outputing zero.

Is there a workaround or proper way to do this ?

Thanks

Answer 1

[VBBV]

syms x(t) y(t) z(x,y) t 
x = x(t);
y = y(t);
z = z(x,y)

z = 

C = diff(z,t)

C = 

[Jaewon Park]

This is great! Thank you.