how can I plot a 3-D helical trajectory

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baris
baris on 15 Feb 2024
Edited: Matt J on 15 Feb 2024
ı need to plot a trajectory like pitcure above but ı could not. Can u help me. the known parameters are that diameter=4 [m], pith (gape) = 2 [m], height = 18 [m]. Also the simulation time is 50 second.

Answers (1)

Matt J
Matt J on 15 Feb 2024
Edited: Matt J on 15 Feb 2024
t=linspace(0,18*pi, 3000);
plot3(2*cos(t), 2*sin(t), t/pi)
  6 Comments
baris
baris on 15 Feb 2024
it is my bad, sir. I thought the pitch is the distance between spirals. I apologize. The known parameters are that if we look over, the helix diameter is 4, the gap beetwen spirals is 2, the heights is 18 and the simulation time is 50 seconds. I also need to get trajectory like down bellow
Matt J
Matt J on 15 Feb 2024
Edited: Matt J on 15 Feb 2024
OK. But what's the problem? Just increase the pitch.
t=linspace(0,4.5*2*pi, 3000);
T=t(end);
s=t(end)/50; %rescale to duration 50
t=t/s;
x=@(t) 2*cos(s*t); y=@(t) 2*sin(s*t); z=@(t)s*18*t/T;
plot3(x(t),y(t),z(t))
figure;
subplot(3,1,1); plot(t,x(t))
subplot(3,1,2); plot(t,y(t))
subplot(3,1,3); plot(t,z(t))

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