How to partition a matrix by sorting a column?

Dear friends:

I want to parttion a matrix into two submatrix by sorting the third column:

For example, the matrix is as follows:

A= [ 73.90  123.17  1.00;
    73.79  121.83 0.00; 
    70.64  74.46  1.00;   
    69.74  86.40  0.00]

I need the output as:

A1= [ 73.90  123.17  1.00;
    70.64  74.46  1.00]

and

A2= [ 73.79  121.83 0.00; 
    69.74  86.40  0.00]

Thank you very much.

Answer 1

[Walter Roberson]

A= [ 73.90  123.17  1.00;
    73.79  121.83 0.00; 
    70.64  74.46  1.00;   
    69.74  86.40  0.00]

A = 4×3

73.9000 123.1700 1.0000 73.7900 121.8300 0 70.6400 74.4600 1.0000 69.7400 86.4000 0

u = unique(A(:,3));

A1 = A(A(:,3)==u(2),:)

A1 = 2×3

73.9000 123.1700 1.0000 70.6400 74.4600 1.0000

A2 = A(A(:,3)==u(1),:)

A2 = 2×3

73.7900 121.8300 0 69.7400 86.4000 0

[Wan-Yi Chiu]

Dear friends

Thanks to you.

Answer 2

[Voss]

A= [ 73.90  123.17  1.00;
    73.79  121.83 0.00; 
    70.64  74.46  1.00;   
    69.74  86.40  0.00]

A = 4×3

73.9000 123.1700 1.0000 73.7900 121.8300 0 70.6400 74.4600 1.0000 69.7400 86.4000 0

C = splitapply(@(x){x},A,findgroups(A(:,end)));

Cell array C contains the matrices you want, A1 and A2

C{:}

ans = 2×3

73.7900 121.8300 0 69.7400 86.4000 0

ans = 2×3

73.9000 123.1700 1.0000 70.6400 74.4600 1.0000

so you don't need to make them separate new variables, but you can

A1 = C{2}

A1 = 2×3

73.9000 123.1700 1.0000 70.6400 74.4600 1.0000

A2 = C{1}

A2 = 2×3

73.7900 121.8300 0 69.7400 86.4000 0