How to increase the precision in my output using structures

Hi guys,

I'm running a program that needs more precision in the output. I have tried to use format long, but the output using the structure still reports without decimal places. Any suggestions?

Thanks

>> a = 3e-6*(s(1).pixels(2)).^2 + 0.0097*(s(1).pixels(2)) + 2.8827

a =

      8

>> s(1).pixels(2)

ans =

    531

>> a = 3e-6*(531).^2 + 0.0097*(531) + 2.8827

a =

    8.8793

Answer 1

[James Tursa]

I would assume s(1).pixels is some type of integer class instead of double, so you are getting an integer result. Either convert s(1).pixels to double first, or wrap the access with a double in the calculation. E.g.,

s(1).pixels = double(s(1).pixels);

or

a = 3e-6*(double(s(1).pixels(2))).^2 + 0.0097*(double(s(1).pixels(2))) + 2.8827