How to perform reverse permute to an already permuted matrix?

Hello, I have taken a color image as input and separated out the R G and B components. And then I converted the three planes into 1 D vectors. Consider a 4x4x3 matrix.The planes are interleaved as follows

V=[r1g1b1....r6]
W=[g6b6r7...g11] 
X=[b11r12...b16]

The following is the code that I used to permute the three planes.

 A=imread('C:\Users\Desktop\lena.jpg');

 R = A(:, :, 1);
 G = A(:, :, 2);
 B = A(:, :, 3);

 R1 = reshape(R.',1,[]);
 G1 = reshape(G.',1,[]);
 B1 = reshape(B.',1,[]);

 H = permute(A, [3 1 2]);

 N = numel(A)/3;
 V = H(1 : N);
 W = H(N + 1 : 2*N);
 X = H(2*N + 1 : end);

Now I need to reverse this function ie; de-interleave the vectors and separate out the three planes and then combine them to get the original image. I dont know how to perform the inverse. I used ipermute function as follows, but i'm not able to obtain a proper result.I have obtained S,T and U which are equal to V,W and X. Dimg is equal to H.

C  = ipermute(Dimg, [3 1 2])

Please help.Thanks in advance.

[David Sanchez]

Who is Dimg?

Did you try:

C = ipermute(H,[3 1 2]);

?

[Vivek Chaudhary]

clc;

%% this program can permute any length vector (row vector)

A=[1 2 3 4 5 6 7 8 9]

M=length(A);

index=randperm(M); %% index

%% permutation

for i=1:M

B(:,i)=A(:,index(i));

z(:,index(i))=i; %% inverse mapping index

end

%% inverse mapping

for j=1:M

A_hat(:,j)=B(:,z(j));

end

A_hat