interpolate data into ODE using interp1 and ode45 problems.

i have a data, x... data of x is a data taken from sinusoidal graph, plus,on its own time sampling like this...

x =

         0         0
   -0.0000   -0.0026
   -0.0000   -0.0050
   -0.0000   -0.0071
   -0.0000   -0.0087
   -0.0000   -0.0097
    0.0000   -0.0100
    0.0000   -0.0096

actually, the data is longer, equivalent to its sampling time and period.

let say i want to use that data to ode equation according to its sampling time... the sampling time for x data is t=0:0.1:100.

so, i try using interpolation. the ode equation is 10d2y/dx2 + 1000dy/dx + 2500000y = 250000s^3

so, here, i want to interpolate x data into s.

below are the codes i tried.

function dxdtt = newforced(t1,b,q,x,t,p3)
dxdtt_1 = b(2);
dxdtt_2 = -100*b(2)-250000*b(1)+(25000*(q^3));
dxdtt = [dxdtt_1;dxdtt_2];

p3=x(:,1);
q=interp(t1,p3,t);
tspan=[0:0.1:100];
initial_dxdtt=0;
initial_b=0;
initial_q=x(2,1);
wrapper=@(t1,x1) newforced(t1,b,x,t,q,p3);
[t1,b]=ode45(wrapper,tspan,[initial_b initial_dxdtt],[initial_q]);

there is too many changes ive done, so im bit confuse...

the problem is, i never got the results. all i got is error. and most frequent error is

Operands to the || and && operators must be convertible to logical scalar values.

Error in interp (line 44)
if l < 1 || r < 1 || cutoff <= 0 || cutoff > 1

Error using newforced (line 2)
Not enough input arguments.

Error in odearguments (line 88)
f0 = feval(ode,t0,y0,args{:});   % ODE15I sets args{1} to yp0.

Error in ode45 (line 114)
[neq, tspan, ntspan, next, t0, tfinal, tdir, y0, f0, odeArgs, odeFcn, ...

any help is greatly appreciated, thanks.