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Difference between a<t<b and t>a && t<b

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Maheen on 28 Apr 2015
Commented: Maheen on 1 May 2015
Hi I am trying to verify existence of even and odd harmonics in e^(-t) periodic with period pi. For that I try to verify f(t)=f(t+pi). and for f(t+pi) i try to add shift using if-else condition according to this link answer should have even harmonics, I am trying to solve Example 2(b) in Matlab.
Now if i use the condition 0<=t(i)<pi it shows me even harmonic but if i use 0>=t(i) && t(i)<pi it gives neither even nor odd.
So, my question is why isn't Matlab showing same result for both formats. and which format is correct.

Accepted Answer

Guillaume on 28 Apr 2015
Edited: Guillaume on 28 Apr 2015
The first form is not going to give you the result you expect, it is equivalent to:
(0 <= t(i)) < pi
Thus, it will compare t(i) to 0, and the result is either 1 (true) or 0 (false). It then compares that 0 or 1 to pi, which is always smaller. Hence the result will always be true.
The second form is the correct one. You can't link comparisons. You have to perform them one at a time and link the results with logical operators.
Ahmet Cecen
Ahmet Cecen on 28 Apr 2015
Thankfully I found only one in a rotation code for visualization. Apparently I like to separate out the conditionals by default. Still many thanks for pointing this out, could have been a disaster. Would give more bumps if I could!
Maheen on 1 May 2015
Thank you So much Guillaume, resolved my problem.

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More Answers (1)

Ahmet Cecen
Ahmet Cecen on 28 Apr 2015
might be because you are supposed to write:
*t(i)>=0 && t(i)<pi*
*0>=t(i) && t(i)<pi*


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