How can I plot 10 shifted single impulses in one plot (in a row)?

I've got 2 impulses with different number of points: imp and S0. I need to plot all impulses together: imp, S0 and the result of adding - 10 impulses Si.

How can I do that?

Thank you!

ub = 10; 

x_imp = linspace(-ub, ub, 1001);
x_S0 = linspace(-ub, ub, 2002);

imp = sech(x_imp);
S0 = sech(x_S0 + ub/2 * sign(x_S0) +ub/2);

figure(1);
plot(x_S0, S0, 'LineWidth', 2, 'Color', 'red');
hold on;
plot(x_imp,imp,'--', 'LineWidth', 3, 'Color', 'blue');

% getting S0 and 10 signals Si
i_steps = 10;           
dt = 10/i_steps;        % shift
Si = zeros(size(x_S0));

for i_steps = 0:10
    shift = i_steps*dt;
    Si = sech (x_S0 + ub/2 * sign(x_S0) + shift);
end

Unrecognized function or variable 'x'.

Answer 1

[Paul]

imp = @(x) sech(x);
S0  = @(x) imp(x).*(x<=0); % assumes S0(0) = sech(0)

ub = 10; 
x_imp = linspace(-ub, ub, 1001);
x_S0 = linspace(-ub, ub, 2002);
figure(1);
plot(x_S0, S0(x_S0), 'LineWidth', 2, 'Color', 'red');
hold on;
plot(x_imp,imp(x_imp),'--', 'LineWidth', 3, 'Color', 'blue');

i_steps = 10;           
dt = 10/i_steps;        % shift
Si = zeros(numel(x_S0),i_steps+1);
for i_steps = 0:10
    shift = i_steps*dt;
    Si(:,i_steps+1) = S0(x_S0 + shift);
end
figure
plot(x_S0,Si)

[Anna_P]

Thank you, @Paul! It worked!