I want to normalize a vector in range -5 to +5. Is it possible?

A vector like v=rand(1,10)*5+1

Answer 1

[Guillaume]

Note that if all you want is generate random numbers between -5 and 5, it's actually one of the examples in the documentation of rand:

r = -5 + (5+5)*rand(10, 1)

Basically, it is

r = lowerbound + (upperbound - lowerbound) * rand

You can of course rescale your vector to whichever range you want:

vrescaled = (v - min(v)) * (newupper - newlower) / (max(v) - min(v)) + newlower

[Aditya Mhetras]

can a vector A=[1 2 3 4 5 6 7 8 9 10] be normalozed in interval -5 to +5?

[Guillaume]

Why couldn't it be? It's a basic linear transformation. As per the formula I've written:

vrescaled = (v - min(v)) * (newupper - newlower) / (max(v) - min(v)) + newlower

where newupper = 5 and newlower = -5, so:

vrescaled = (v - 1) * 10 / 9 - 5;

Answer 2

[Andrei Bobrov]

As wrote Guillaume:

variant 1:

out = A - 5; % if A >= 0 & A<=10

variant 2:

m = min(A(:));
out = (A(:)-m)/(max(A)-m)*10-5;