Sorting a cell array

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Yongmin
Yongmin on 17 Jun 2015
Commented: Yongmin on 17 Jun 2015
Hello, I have the following cell(data, 1x3):
data = [data{1} data{2} data{3}]
data{1} data{2} data{3}
A 15 1400
A 3 250
B 10 1100
C 13 1350
B 7 600
Now I would like to sort the data and make a new cell as follows:
newcell = [newcell{1} newcell{2} newcell{3}]
newcell{1} newcell{2} newcell{3}
A [15; 3] [1400; 250]
B [10; 7] [1100; 600]
C [13] [1350]
In other words, I want to sort and save the data of a cell with respect to A, B and C. Would you please show me how to do that with or without using for loop etc?
Thanks in advance.
  2 Comments
Yongmin
Yongmin on 17 Jun 2015
I guess the problem can be solved without the loop. If we find idx matrix describing the elements for A, B, and C, can we use the idx matrix for sorting data{2} and data{3}? But I don't know how to do it exactly.
If we use a for loop, would you please explain how to do it?
Thanks for your comment.

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Accepted Answer

Guillaume
Guillaume on 17 Jun 2015
data = {'A' 15 1400; 'A' 3 250; 'B' 10 1100; 'C' 13 1350; 'B' 7 600}
[header, ~, row] = unique(data(:, 1));
catcol = @(col) arrayfun(@(r) [data{r == row, col}], 1:numel(header), 'UniformOutput', false)';
newcell = [header, catcol(2), catcol(3)]
would be one way to do it without a loop. It could be made even more generic with an additional arrayfun looping over the columns, but at this point, you'd be better off using a for loop to make it clearer.
  3 Comments
Yongmin
Yongmin on 17 Jun 2015
Thanks a lot for your kind answer. It will help to develop codes for my problem.

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