MATLAB Answers


Bug about saving a variable

Asked by Isaac
on 19 Dec 2011
Hello everybody,
i am experiencing a very strange bug in saving a variable.
Supposing variable name is "xxxxx"
if i execute the instruction
save filetarget xxxxx (which should save the xxxxx variable in the filetarget.mat file)
and then i execute
load filetarget
i receive the following error message: Error using ==>load Unable to read MAT-file C:\....filetarget.mat File may be corrupt
but if i create a variable with a shorter name, that is
and then i execute save filetarget x and then load filetarget
everything works...
what can it be??
Thanks in advice!!!!


Daniel Shub
on 19 Dec 2011
It works fine on my system. Are your variables really only 5 characters long?
Walter Roberson
on 19 Dec 2011
Could you show us the actual variable name you are having problems with?
Which MATLAB version are you using, and which MS Windows version?

Sign in to comment.


3 Answers

Answer by Naz
on 19 Dec 2011

yourfile='name.mat'; %saves in the current directory
save yourfile x
load yourfile
Strange... I don't get an error when using variable xxxxx. Maybe matlab has an issue with the path where you want to save it? Try saving it in the current directory first.
Try using this set:
save(yourfile, 'xxxxx');
where the 'new' variable will be a struct containing your variable xxxxx. To access it, you need this reference:


Show 1 older comment
Walter Roberson
on 19 Dec 2011
What? No, that would save to yourfile.mat not to name.mat !
save(yourfile, 'x') would be the code.
on 19 Dec 2011
In the code above, the variable 'x' is in the file 'name'.
Walter Roberson
on 19 Dec 2011
I'm pretty sure that is not true, Naz.
save yourfile x
is taking advantage of command / function duality such as is described briefly by Steve at
save yourfile x
would be treated as
which would save to the file named yourfile.mat
If you examine the save() documentation at you will see that in each case where command/function duality is used, the filename given is treated literally rather than being evaluated. For example "save test.mat" does not attempt to extract the field named "mat" from the structure variable "test" and use the value of the field as the file name.

Sign in to comment.

>> xxxxxxx=rand(3);
>> save filetarget xxxxxxx
>> clear all
>> whos
>> load filetarget
>> whos
Name Size Bytes Class Attributes
xxxxxxx 3x3 72 double
>> display(xxxxxxx)
xxxxxxx =
0.4898 0.7094 0.6797
0.4456 0.7547 0.6551
0.6463 0.2760 0.1626


Sign in to comment.

Answer by Isaac
on 20 Dec 2011

I explained myself in a wrong way. The problem is not "usual": saving and loaind usually works well with me, whatever is the name and its length of the variable.
The problem is about one specific variabile... which i dunno why if i save it and then load it .... it tells me that error message "Error using ==>load Unable to read MAT-file C:\....filetarget.mat File may be corrupt" but, more surprisingly, if i save it with another name... it works!!!!
that is:
variable "var1"
save filetarget var1 load filetarget ERROR
var2=var1 save filetaget var2 load filetarget
Everything works....


on 20 Dec 2011
the name is "rendimentoSTOXX600"
but i think it should be something else than name... because the same problems is given by another variable which is calculated from "rendimentoSTOXX600"
on 20 Dec 2011
Please post running code and format it as explained in the "Markup help"link on this page.
on 20 Dec 2011
Are you sure, that this is not working:
var1 = rand(10);
save filetarget var1
Data = load('filetarget.mat');

Sign in to comment.