I want to change binary to an array and vice vera

I need to be able to change [1 0 1 1 0] to 10110

also its required that i do the opposite eg. 10110 to [1 0 1 1 0]

This has to work for all binary numbers and also for decimal numbers, I have done a lot of research and trying different things but I have not found any solution.

For the assignment I only have one line to spare but if needs be I can cut somewhere else if i need to,

also would anybody be able to explain what a string is, i think its related to what I'm trying to achieve,

thanks.

[per isakson]

Is this homework? I assume that "binary" is a string. Hint:

• sprintf creates a string from a numeric
• sscanf can read digits from a string

"explain what a string is" &nbsp see String handling

Answer 1

[Image Analyst]

This little trick is shown frequently in this forum:

% Start with a logical variable vector
m = logical([1 0 1 1 0]) % Change to '10110'
% First convert to a string.
string = sprintf('%d', m)
% Convert the string back to a logical.
logicalVector = string - '0'

Answer 2

[Walter Roberson]

dec2bin([1 0 1 1 0])'

[DavHor]

sorry i have the binary and decimal numbers found i need to be able to change how they are displayed eg in a number or array

[Walter Roberson]

dec2bin(123)

If you have values that are not integral then there is no standard way of converting them to binary for printed representation.

Answer 3

[Star Strider]

To change a decimal scalar or a concatenated binary number (represented as a scalar) into a vector of its digits, this works for positive integers:

b = 10110;                                  % Binary String As Double Scalar
lb = ceil(log10(b));                        % Length Of ‘b’
for k1 = 1:lb
    d(k1) = rem(b,10);
    b = floor(b/10);
end
d = flip(d)                                 % Vector Of ‘b’

d =
     1     0     1     1     0

There are likely more efficient and robust methods. This is probably the most obvious.