Variable in parfor cannot be classified
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I've looked for answers on this forum but each situation seems to different from mine. My code sends some data to a function which outputs many variables which are defined as sets of tau coefficients (or a tau by tau matrix) on a Nx by Ny mesh.
Here is my code:
speedmaxF = 0;
system_cell = NaN(tau,Nx,Ny);
trunc_east = NaN(tau,Nx,Ny);
trunc_west = NaN(tau,Nx,Ny);
Jac_trunc_east = NaN(tau,tau,Nx,Ny);
Jac_trunc_west = NaN(tau,tau,Nx,Ny);
Jac_cell = NaN(tau,tau,Nx,Ny);
Jac_east_cell = NaN(tau,tau,Nx,Ny);
Jac_west_cell = NaN(tau,tau,Nx,Ny);
Jac_east_other = NaN(tau,tau,Nx,Ny);
Jac_west_other = NaN(tau,tau,Nx,Ny);
flux_east = NaN(tau,Nx,Ny);
flux_west = NaN(tau,Nx,Ny);
DGprev_ghosts_east = NaN(tau,Nx,Ny);
DGprev_ghosts_west = NaN(tau,Nx,Ny);
DGprev_ghosts_east(:,1:(end-1),:,:) = DGprev_ghosts(:,2:end,:,:);
DGprev_ghosts_west(:,2:end,:,:) = DGprev_ghosts(:,1:(end-1),:,:);
parfor index1 = 1:Nx
for index2 = 1:Ny
qstar = DGprev_ghosts(:,index1,index2);
qeast = DGprev_ghosts_east(:,index1,index2);
qwest = DGprev_ghosts_west(:,index1,index2);
v1center = v1centers(index1);
v2center = v2centers(index2);
cellcenter = [v1center v2center];
[trunc_east(:,index1,index2),trunc_west(:,index1,index2), ...
flux_east(:,index1,index2), flux_west(:,index1,index2), ...
Jac_east_cell(:,:,index1,index2),Jac_west_cell(:,:,index1,index2), ...
Jac_east_other(:,:,index1,index2),Jac_west_other(:,:,index1,index2), ...
Jac_trunc_east(:,:,index1,index2),Jac_trunc_west(:,:,index1,index2), ...
Jac_cell(:,:,index1,index2),system_cell(:,index1,index2),maxspeedF] ...
= predictor_precompute_eastwest(qstar,qeast,qwest,qstar,data,cellcenter);
speedmaxF(iv1ghost) = max([speedmaxF(iv1ghost) maxspeedF]);
end
end
The error message is:
Error: File: predictor_main.m Line: 146 Column: 10
The variable trunceast in a parfor cannot be classified.
See Parallel for Loops in MATLAB, "Overview".
I have tried by adding things like truncteast = trunceast after the loop, but nothing seems to work. Suggestions?
3 Comments
Walter Roberson
on 18 Feb 2016
Yes, that is an appropriate approach: write into a temporary vector in the inner loop, and assign the vector as a whole to the appropriate output space in the outer loop.
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