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X = [67;89;78;56;55;75;99];

f = [4;5];

for i = 1:length(X);

if i == f;

X1(i,1) = 5*X(i,1);

else

X1(i,1) = X(i,1);

end

end

I know that the way i have written the if expression is wrong but can someone tell how do I write the if expression such that it uses the values of f.. basically if i equals the value in the f matrix or array the first formula is used else the second.

Thanks for help.

Sid

Arnab Sen
on 25 Feb 2016

Hi Siddharth,

My understanding from your problem statement that you want to check whether the values of the variable 'i' is present in the vector 'f' in the if-statement. You can use in-built 'find' function for this purpose. 'find' function returns the indices of the vector which meet certain condition. If no match then it returns a empty vector. So you can write the if statement in the following way:

>>if(~isempty(f==i))

So, the whole script as below:

if true

% code

end

X = [67;89;78;56;55;75;99];

f = [4;5];

for i = 1:length(X);

%if i == f

if(~isempty(find(f==i)))

X1(i,1) = 5*X(i,1);

else

X1(i,1) = 1*X(i,1);

end

end

For more detail about 'find', refer to the following link:

Walter Roberson
on 25 Feb 2016

Edited: Stephen Cobeldick
on 25 Feb 2016

ismember(i, f)

Or, you can use

X1 = X;

X1(f) = 5 * X(f);

with no loop.

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