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Say I have an array in a .csv file like this:

a,b,c,d,e,f

20,1,10,100,1000,100

21,2,20,200,2000,200

22,3,30,300,3000,300

23,4,40,400,4000,400

24,5,50,500,5000,500

25,6,60,600,6000,600

and I want to solve this set of equations for g, h, and k:

f(a)=((((b-c)*g)/((d-e)*h))^f)+k

f(a+1)=((((b-c)*g)/((d-e)*h))^f)+k

f(a+2)=((((b-c)*g)/((d-e)*h))^f)+k

If I wanted to solve this set of equations using the values in the first three rows of data, and then solve the same three equations using the values in the second three rows and continue the evaluation for n rows of data, how would I set that up? I was thinking of defining each term in the equation as a csvread (b=csvread(filename, row, column)), but I don't know hot to handle the reading of different rows by a regular increase (3 rows at a time through the whole dataset). Any ideas?

Thanks.

Bård Skaflestad
on 30 Jan 2012

What are you actually trying to accomplish? Is it to solve a sequence of systems of three (highly) non-linear equations defined more or less by

G(X, Y1) == 0

G(X, Y2) == 0

G(X, Y3) == 0

in which X=[g,h,k], Y=[a,b,c,d,e,f], and

f1 = @(x, y) x ./ y;

f2 = @(x, y, z) (x - y) .* z;

f3 = @(x, y, z, w) f1(x, y).^z + w

f4 = @(b, c, d, e, f, g, h, k) ...

f3(f2(b, c, g), f2(d, e, h), f, k) - f

G(X,Y) = f4(Y(2), Y(3), Y(4), Y(5), Y(6), ...

X(1), X(2), X(3))

If so, you need to devise a method for solving a single such system given a particular set of parameters a..k . Then, solving a sequence of such systems is a trivial loop (typically stride three) over the rows of the data matrix input using csvread.

If the above is not what you're after, then you will need to be a lot more precise concerning what you want to accomplish. And do, please, include the details of what you've done so far.

Bård Skaflestad
on 1 Feb 2012

I'm adding another answer based on your comment to my previous answer. I wanted to simply add another comment, but I need code markup (and the most up-voted answer to question 994 also points out the lack of markup capabilities in comments...)

Anyway, this is a perfect case for closures (effectively, parametrised function handles). I'd write a simple generator function like

function F = generate_system(p)

assert (ndims(p) == 2, ...

'System parameters ''P'' must be 2D matrix.');

assert (all(size(p) == [3, 5]), ...

'System parameters must be 3-by-5 matrix.');

b = p(:,1);

c = p(:,2);

d = p(:,3);

e = p(:,4);

f = p(:,5);

q = (b - c) ./ (d - e);

F = @(x) (q .* x(1) / x(2)).^f + x(3) - f;

end

which, when called with parameter matrix p consisting of three consecutive rows of the parameter data from your .csv file, will return a function handle that defines a particular system of non-linear equations. This handle can be passed on to fsolve along with an initial guess to affect the numerical solution of this particular system.

Given generate_system above, you can solve the sequence of non-linear systems using a script like the following

data = csvread('data.csv');

assert (mod(size(data, 1), 3) == 0, ...

'Input data must have an integer multiple of 3 rows');

assert (size(data, 2) == 6, ...

'Input data must have exactly six columns.');

nsys = size(data, 1) / 3;

soln = zeros([nsys, 3]);

for k = 1 : nsys,

F = generate_system(data(3*k + (1:3), 2:end));

X0 = some_initial_guess;

soln(k, :) = fsolve(F, X0);

end

at least if all of the individual systems have a solution.

I'm afraid I don't have the Optimization Toolbox installed, so I cannot actually test this thing. Hopefully, it will at least provide some hints as to how to proceed.

Bård Skaflestad
on 1 Feb 2012

No problem. Of course I did make an error in the parameter subset extraction. It should be

F = generate_system(data(3*(k-1) + (1:3), 2:end))

Terribly sorry about that.

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