Sorting a matrix from smallest to biggest left to right

I made this code here for a matrix that was only 1 row. Now that I have matrices with multiple rows I don't know how to make it sort from left to right. Right now it sorts from top to bottom.

For example, the third matrix goes

4 7

5 8

6 9

I need it to go

4 5

6 7

8 9

 m=numel(a); 
 for j=1:1:(m-1)
    for i=1:1:(m-1)
        if a(i)>a(i+1)
            temp=a(i);
            a(i)=a(i+1);
            a(i+1)=temp;
        end
    end
end

These are some of the matrices I need to work with

 a=[3 -2 1;4 0 5;1 2.2 -3]
 a=[4 2 1;9 3 5]
 a=[9 8;7 6;5 4]

Any help is appreciated. Thank you.

Answer 1

[Stephen23]

The trick is to transpose, then use the columnwise element order:

>> M = [4,7;5,8;6,9]
M =
     4     7
     5     8
     6     9
>> tmp = M.';
>> tmp(:) = sort(tmp(:));
>> out = tmp.'
out =
     4     5
     6     7
     8     9

Basically what you are doing is simple, when you think in terms of columns, not rows.

[Vinny]

The only issue is I can't use built in functions like sort, so I need a way to have it do this in the loop.

Answer 2

[Andrei Bobrov]

M = [4,7;5,8;6,9]

out = reshape(M,size(M,2),[])';

[Vinny]

I've integrated this into the loop and it works and gives me the matrix the way I want it.

 for j=1:1:(m-1)
    for i=1:1:(m-1)
        if a(i)>a(i+1)
            temp=a(i);
            a(i)=a(i+1);
            a(i+1)=temp;
            out=reshape(a,size(a,2),[])';
        end
    end
end

But for this assignment I can't use built in functions like reshape. How can this be done as a loop?