How to add rows to a mtrix following a certain condition?

Suppose the following matrix r= [0; 1; 1.5; 1.6; 2; 10.4; 15.5].

How to add rows which are in the interval floor(r):0.1:floor(r)+1?

In the end, the output should be:

r_out = [0; 0.1; 0.2; ...; 1; 1.1; 1.2; ...; 2; 2.1; ...; 3; 10; 10.1; ...; 11; 15; 15.1; 15.2 ; ...; 16]

I have tried the following:

for i=1:size(r,1); p = floor(r(i)):0.1:floor(r(i))+1; q = [r; p']; end

However, it does not cover all the elements. Probably, the loop is erasing previous computation after each update.

[Image Analyst]

Is this homework? What have you tried so far?

[Anderson]

No, this is absolutely not a homework!

I have tried the following:

for i=1:size(r,1); p = floor(r(i)):0.1:floor(r(i))+1; q = [r; p']; end

However, it does not cover all the elements. Probably, the loop is erasing previous computation after each update.

[Anderson]

I found the problem.

r=unique(r, 'rows', 'stable');

for i=1:size(r,1); p(i,:) = floor(r(i)):0.1:floor(r(i))+1; end

q = unique(reshape(p,[],1));

Answer 1

[Fangjun Jiang]

r= [0; 1; 1.5; 1.6; 2; 10.4; 15.5];

rf=unique(floor(r));
r_out=bsxfun(@plus,rf.',(0:0.1:1).');
r_out=r_out(:);

The output is slightly different than what you listed. The difference is the elements of [2:0.1:3]. Not sure which one should be correct based on your post.

Answer 2

[Anderson]

I found the problem.

r=unique(r, 'rows', 'stable');

for i=1:size(r,1); p(i,:) = floor(r(i)):0.1:floor(r(i))+1; end

q = unique(reshape(p,[],1));