how to insert the column [60;80] into the third column

A=[1 5 6; 3 0 8]

Answer 1

[Azzi Abdelmalek]

A=[1 5 6; 3 0 8]
A=[A [60;80]]

%Or

A(:,end)=[60;80]

[Image Analyst]

This appends. It does not insert. The data are not even in column 3 - they're in column 4. Even though my code is longer because of comments and error checking, I think it's the most robust, and it will insert or append depending on how many columns there are already.

Answer 2

[Image Analyst]

Bella, here's a fairly robust way:

% Define sample data.
A=[1 5 6; 3 0 8]
[rows, columns] = size(A);
% Define a column vector of data you'd like to insert.
colVecToInsert = [60;80]
% Define the column you want to insert it to
col = 3;
% Do the insert
if col >= 1 && col <= (columns + 1)
  A = [A(:,1:col-1), colVecToInsert, A(:, col:end)]
elseif col > (columns + 1)
  % Will append to right side.
  A = [A, colVecToInsert]
else
  warningMessage = sprintf('Cannot insert into column %d', col);
  uiwait(warndlg(warningMessage));
end

[Ahmet Cecen]

Ooh I see what the question meant now.

Answer 3

[Ahmet Cecen]

 A(:,3) = A(:,3) + [60;80];

[Bella]

i meant, how do you put the result back into that column.. not add the two

[Bella]

figured it out, thanks

[Ahmet Cecen]

This is putting it back into that column.

Answer 4

[Jos (10584)]

A = [1 5 6 ; 0 3 8]
A(:,3) = [60 ; 80] % insert a vector in the 3rd column

[Image Analyst]

This overwrites, not inserts.

[Jos (10584)]

True, but isn't there a difference between "insert into" and "insert before"/"insert after"? Confusing question → different answers.

Answer 5

[Jos (10584)]

For what it is worth, take a look at INSERTROWS, which you can use with transpose to get "insertcolumns" after (or before) a specific column

A = [1 5 6 ; 3 0 8] 
B = [60 ; 80]
ColumnToInsertB_before = 3
C = insertrows(A.', B.', ColumnToInsertB_before-1).'

The function INSERTROWS can be downloaded via this link: http://blogs.mathworks.com/pick/2008/05/16/inserting-rows/