How to convert a file containing real numbers into binary/hexadecimal?

I want to convert whole file of real numbers having atleast 1000 data points into binary/hex using some function or program. Plz help

Answer 1

[Walter Roberson]

num2hex() is the routine to use to see the hex representation of the IEEE 754 bit pattern for float or double.

[MEENU SAINI]

yes num2hex() is working for files containing real numbers. Thanks a lot for your reply!!

Answer 2

[Azzi Abdelmalek]

You can use dec2bin and dec2hex function

[Walter Roberson]

No, that only works for non-negative integers.

Answer 3

[MEENU SAINI]

but there is some problem in the converted data. I have converted a file containing 1000 real numbers to hexadecimal using this function num2hex(). The real numbers are like:

-0.0128380000000000

-0.0142530000000000

-0.0080360000000000

-0.0120290000000000

-0.0136970000000000

-0.0268890000000000

-0.0320450000000000

-0.0295180000000000 & so on upto 1000.

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The converted hex file is looking like:

bf8a4acf312b1b37

bf8d30ad46f587d7

bf80752da98676a7

bf88a2a90cd423d9

bf8c0d2c386d2ed8

bf9b88ca3e7d1351

bfa06833c60029f1

bf9e39f77292c493

--

but I think it should be like:

0xbc52567a

0xbc69856a

0xbc03a96d

0xbc451548

0xbc606962

0xbcdc4652

0xbd03419e

--

Is there any solution to this? Plz reply

[Walter Roberson]

The outputs are correct for double precision numbers, but you happen to be looking for output for single precision numbers. Apply single() to the numbers and num2hex() the result. Alternately you can use something like

 char(arrayfun(@(x) sprintf('0x%08x', typecast(single(x), 'uint32')), YourArray(:), 'Uniform', 0))

or

num2str(typecast(single(YourArray(:)),'uint32'), '0x%08x')

[MEENU SAINI]

Thank you Sir!! I have one more problem that after processing this converted data file, I need to convert this hex file back to real data file. So what function should I use? Plz help!

[Walter Roberson]

https://www.mathworks.com/matlabcentral/newsreader/view_thread/30803