Why is de2bi not working for large decimal number?

I am using de2bi in an attempt to convert from 1582000000 to a 32 digit binary number.

data=de2bi(data,32,2,'left-msb'); where data is 1582000000.

The left-most 16 digits are correct, but the right-most 16 digits are not. What am I doing wrong??

Thanks!

Answer 1

[Massimo Zanetti]

You are doing anything wrong.

But, using option 'left-msb' you are telling Matlab to consider right digits as higher order. So you get an "inverted" binary number. Maybe you want to use the classical binary representation with right-most higher order digits.

data=1582000000;
d=de2bi(data,32,2);
%check
n=bi2de(d)

[Sara Stout-Grandy]

Thanks. I didn't realize I was doing an inversion, I thought the 'left-msb' option was literally just supposed to swap the bits. Is there a way to swap the bits then so the MSB is the left more digit? Thanks!

[Massimo Zanetti]

Yes basically the 'left'msb' swaps the bits from right to left (it flips the whole bytes), infact you have:

de2bi(data,32,2,'left-msb')==flip(de2bi(data,32,2))

If this answer heped you, please accept :)