how i can solve this problem

y= [2.97-j*35.24 -0.99+j*9.9 0 0 0 -1.98+j*19.8
-0.99+j*9.9 2.97-j*38.59 j*9.43 0 0 -1.98+j*19.8;
0 j*9.43 17.65-j*39.41 -17.65+j*29.41 0 0;
0 0 -17.65+j*29.41 17.65-j*49.41 j*20 0;
0 0 0 j*20 -j*20 0;
-1.98+j*19.8 -1.98+j*19.8 0 0 0 3.96-j*39.59;];
% the initial values for the required below variables are
x1=1.05;
x2=1.0476 + j*0.0472;
x3=0.9727 + j*0.1433;
x4=0.9836 + j*0.1704;
x5=0.9755 + j*0.2198;
x6=1.0491 + j*0.0236;
d=1-j*0.0536;
f=0;
I=-0.9338 -j*0.1070
% the required equations to solve
I=y(1,1)*x1+y(1,2)*x2+y(1,6)*x6;
% where the value of I depends on the value of x1 and initial valur for I=-0.9338 -j*0.1070
I=((1.0693 -j*0.1681)-x1)/(j*0.18);
f=x2/(j*0.4);
f=-(y(2,3)*x3+y(2,6)*x6+y(1,1)*x1+y(2,2)*x2);
x3=-(y(3,4)*x4+y(3,2)*x2)/y(3,3);
x4=-(y(4,3)*x3+y(4,5)*x5)/y(4,4);
x5=(d-y(5,4)*x4)/y55;
% note d has initial value d=1-j*0.0536 and depends on x5 d=1-x5
d=1-x5
x6=-(y(6,1)*x1+y(6,2)*x2)/y66;
%i want to iterate the above equation to find the values of x1,x2,x3,x4,x5,x6 and the values of I,d,f

Answers (1)

Kylynn Blair
Kylynn Blair on 2 Apr 2020
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