How to plot two equation consequetively

Hi, I have written this code and need to plot jlralph and jlrgamma in a continuous way from 0 to alpharange and alpharange to alpharange2 respectively.

        mc0 = -0.5;
           jlr0 = -0.8;
            M = 0.99;
            alpharange = 6.5; %// degrees
            alpharange2 = 180; %// degrees

           mcalpha = (mc0 - (1 / M) - 1) * cos(alpharange) + jlr0 * sin(alpharange) + (1/M) + 1
 jlralpha = ((-mc0) + (1 / M) + 1) * sin(alpharange) + jlr0 * cos(alpharange)
            for i=0:1:alpharange

                             jlralph = ((-mc0) + (1 / M) + 1) * sin(i) + jlr0 * cos(i)

                for x=alpharange:1:alpharange2

                    jlrgamma = ((-mcalpha) + (1 / M) - 1) * sin(x- alpharange) + jlralpha * cos(x- alpharange);

                end

            end

How do I do that

Answer 1

[Walter Roberson]

mc0 = -0.5;
jlr0 = -0.8;
M = 0.99;
alpharange = 6.5; %// degrees
alpharange2 = 180; %// degrees

mcalpha = (mc0 - (1 / M) - 1) * cosd(alpharange) + jlr0 * sind(alpharange) + (1/M) + 1;
jlralpha = ((-mc0) + (1 / M) + 1) * sind(alpharange) + jlr0 * cosd(alpharange);

%above here I only changed sin to sind and cos to cosd

%below here is vectorized computations. Note sin and cos changed to sind and cosd

alpha1 = linspace(0, alpharange);
jlralph = ((-mc0) + (1 / M) + 1) * sind(alpha1) + jlr0 * cosd(alpha1);

alpha2 = linspace(alpharange, alpharange2);
jlrgamma = ((-mcalpha) + (1 / M) - 1) * sind(alpha2 - alpharange) + jlralpha * cosd( alpha2 - alpharange);

plot([alpha1, alpha2], [jlralph, jlrgamma])

[safi58]

Thank you walter.